Quantitative Aptitude Practice Question and Answer
8Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 4146 05b5cc6dee4d2b4197774ea65
5b5cc6dee4d2b4197774ea65- 120true
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.
Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 4137 05b5cc69de4d2b4197774c8b2
5b5cc69de4d2b4197774c8b2- 188true
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Answer : 1. "88"
Explanation :
Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676 Hence the missing number in the given number series is 88.
Q: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 4132 05b5cc73de4d2b4197774f91b
5b5cc73de4d2b4197774f91b- 110true
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Answer : 1. "10"
Explanation :
Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.
Q: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 4130 05b5cc75ee4d2b4197774fcb1
5b5cc75ee4d2b4197774fcb1- 16:31false
- 211:30false
- 37:30true
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Answer : 3. "7:30"
Explanation :
Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30 Therefore, the ratio is 7 : 30
Q: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part ? 4108 05b5cc6e2e4d2b4197774ec5c
5b5cc6e2e4d2b4197774ec5c- 142true
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Answer : 1. "42"
Explanation :
Answer: A) 42 Explanation: Let x and y be the two parts of 96. x/7 = y/9 => x:y = 7:9 => The smallest part is = 7/16 x 96 = 42.
Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4105 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
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Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.
Q: The number of ways in which 8 distinct toys can be distributed among 5 children? 4103 05b5cc699e4d2b4197774c700
5b5cc699e4d2b4197774c700- 15P8false
- 25^8true
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Answer : 2. "5^8"
Explanation :
Answer: B) 5^8 Explanation: As the toys are distinct and not identical, For each of the 8 toys, we have three choices as to which child will receive the toy. Therefore, there are 58 ways to distribute the toys. Hence, it is 58 and not 85.
Q: 194, 194, 191, 183, 168, ? Find the next number in the above series? 4094 05b5cc6bce4d2b4197774d872
5b5cc6bce4d2b4197774d872- 1154false
- 2156false
- 3144true
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Answer : 3. "144"
Explanation :
Answer: C) 144 Explanation: Here the series follows, 194 194 - (1x1 - 1) = 194 194 - (2x2 - 1) = 191 191 - (3x3 - 1) = 183 183 - (4x4 - 1) = 168 168 - (5x5 - 1) = 144