Quantitative Aptitude Practice Question and Answer
8Q: 3 is what percent of 5? 1959 05b5cc64ae4d2b4197774bc0c
5b5cc64ae4d2b4197774bc0c- 145%false
- 260%true
- 372%false
- 480%false
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Answer : 2. "60%"
Explanation :
Answer: B) 60% Explanation: Here it is asked that 3 is what percent of 5 Let 3 is K percent of 5. => K x 5/100 = 3 => K = 300/5 = 60 Hence, 3 is 60% of 5.
Q: On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? 1959 05b5cc741e4d2b4197774f9a4
5b5cc741e4d2b4197774f9a4- 114false
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Answer : 4. "15"
Explanation :
Answer: D) 15 Explanation: Let 'K' be the total number of sweets.Given total number of students = 112If sweets are distributed among 112 children,Let number of sweets each student gets = 'L' => K/112 = L ....(1)But on that day students absent = 32 => remaining = 112 - 32 = 80Then, each student gets '6' sweets extra. => K/80 = L + 6 ....(2)from (1) K = 112L substitute in (2), we get112L = 80L + 48032L = 480L = 15 Therefore, 15 sweets were each student originally supposed to get.
Q: Derivative of sinx by first principle? 1957 05b5cc6abe4d2b4197774d011
5b5cc6abe4d2b4197774d011- 1-sinxfalse
- 2-cosxfalse
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Answer : 3. "cosx"
Explanation :
Answer: C) cosx Explanation: Thus, the derivative of sinx by first principle is cosx.
Q: A train covers 180 km distance in 5 hours. Another train covers the same distance in 1 hour less. What is the difference in the distances covered by these trains in one hour if they are moving in the same direction? 1956 05b5cc6a3e4d2b4197774cbff
5b5cc6a3e4d2b4197774cbff- 115 kmsfalse
- 29 kmstrue
- 36 kmsfalse
- 418 kmsfalse
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Answer : 2. "9 kms"
Explanation :
Answer: B) 9 kms Explanation: The first train covers 180 kms in 5 hrs => Speed = 180/5 = 36 kmph Now the second train covers the same distance in 1 hour less than the first train => 4 hrs => Speed of the second train = 180/4 = 45 kmph Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.
Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 1952 05b5cc709e4d2b4197774f262
5b5cc709e4d2b4197774f262- 149450false
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Answer : 2. "50540"
Explanation :
Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed), Total : C121×C320+C321×C120= 50540 ways.
Q: Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ? 1952 05b5cc745e4d2b4197774fa54
5b5cc745e4d2b4197774fa54- 164false
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Answer : 3. "71"
Explanation :
Answer: C) 71 Explanation: To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51). Therefore, HCF of 923, 1207 and 1349 is 71.
Q: If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ? 1951 05b5cc731e4d2b4197774f7fb
5b5cc731e4d2b4197774f7fb- 16false
- 28false
- 34true
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Answer : 3. "4"
Explanation :
Answer: C) 4 Explanation: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Q: The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ? 1950 05b5cc736e4d2b4197774f83c
5b5cc736e4d2b4197774f83c- 184 km/hrtrue
- 296 km/hrfalse
- 372 km/hrfalse
- 460 km/hrfalse
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Answer : 1. "84 km/hr"
Explanation :
Answer: A) 84 km/hr Explanation: Let the speeds of the car, train and bus be 5x, 9x and 4x km/hr respectively.Average speed = 5x + 9x + 4x/3 = 18x /3 = 6x km/hr.Also, 6x = 72 => x = 12 km/hrTherefore, the average speed of the car and train together is = 5x+9x2= 7x = 7 x 12 = 84 km/hr.