Quantitative Aptitude Practice Question and Answer
8Q: Find the Odd One Out? 3, 4, 14, 48, 576, 27648 2227 05b5cc6b0e4d2b4197774d2c6
5b5cc6b0e4d2b4197774d2c6- 14false
- 214true
- 348false
- 427648false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: Given Number series is : 3 4 14 48 576 27648 It follows a pattern that, 3 4 4 x 3 = 12 but not 14 12 x 4 = 48 48 x 12 = 576 576 x 48 = 27648 Hence, the odd one in the given Number Series is 14.
Q: What are the Multiples of 6 and the Common Multiples of 4 and 6? 2227 05b5cc6b1e4d2b4197774d303
5b5cc6b1e4d2b4197774d303- 112, 34, 42false
- 212, 18, 36,true
- 36, 4, 14false
- 44, 8, 16false
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Answer : 2. "12, 18, 36,"
Explanation :
Answer: B) 12, 18, 36, Explanation: The Multiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48, 54, 60. The Multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60. The Common Multiples of 4 & 6 upto 60 numbers are given as 12, 24, 36, 48, 60.
Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2227 05b5cc73ae4d2b4197774f902
5b5cc73ae4d2b4197774f902- 114.69 cmfalse
- 229.39 cmtrue
- 318.65 cmfalse
- 422.21 cmfalse
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Answer : 2. "29.39 cm"
Explanation :
Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms. As speed is same, area of cross sections should be same. Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 i.e πR2 = 6πR12 Here R = R and R1 = 12/2 = 6 ⇒R2 = 6×6×6 R = 14.696 => D = X = 14.696 * 2 = 29.3938 cm.
Q: 1397 x 1397 = ? Here what replaces '?' 2223 05b5cc6bbe4d2b4197774d853
5b5cc6bbe4d2b4197774d853- 11951609true
- 21821504false
- 32031489false
- 41847879false
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Answer : 1. "1951609"
Explanation :
Answer: A) 1951609 Explanation: 1397 x 1397
Q: On her deathbed, a grand mother called upon his three grand sons and told them to distribute all her assets worth Rs. 52,500 in the ratio of 1/35 : 1/21 : 1/15 amongst themselves. Find the smallest share amongst the three portions ? 2222 05b5cc761e4d2b4197774fd3f
5b5cc761e4d2b4197774fd3f- 1Rs. 5422false
- 2Rs. 10,500true
- 3Rs. 12,800false
- 4Rs. 15,000false
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Answer : 2. "Rs. 10,500"
Explanation :
Answer: B) Rs. 10,500 Explanation: The ratio of distribution should be: 21 x 15 : 15 x 35 : 35 x 21= 315 : 525 : 735 = 3 : 5 : 7The smallest share will be of worth: 3/15 x 52,500 = Rs. 10,500
Q: Swetha when get married to Sudeer her age was 3/4 th of her husband's age. After 12 years her age became 5/6 th of her husband's age. Then what's the age of Swetha when she got married ? 2221 05b5cc71be4d2b4197774f55e
5b5cc71be4d2b4197774f55e- 118 yearstrue
- 221 yearsfalse
- 323 yearsfalse
- 417 yearsfalse
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Answer : 1. "18 years"
Explanation :
Answer: A) 18 years Explanation: At the time of marriage, let Sudeer's age be 4x, then Swetha's age is 3x12 years after:Age of Sudeer = 4x+12Age of Swetha = 3x+12Now the equation is 3x+12=5/6(4x+12)Solving equation we get x=6Hence Swetha got married at the age of 18.
Q: Find the odd one in the given series ? 5-20-25, 10-40-50, 4-15-24, 25-100-125 2220 05b5cc6dde4d2b4197774e9ec
5b5cc6dde4d2b4197774e9ec- 14-15-24true
- 25-20-25false
- 310-40-50false
- 425-100-125false
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Answer : 1. "4-15-24"
Explanation :
Answer: A) 4-15-24 Explanation: In each term second two numbers are multiples of the first number. But in 4-15-24 15 is not multiple of 4.
Q: If a trader sold two cars each at Rs. 404415 and gains 15% on the first and loses 15% on the second, then his profit or loss percent on the whole is ? 2217 05b5cc6d8e4d2b4197774e732
5b5cc6d8e4d2b4197774e732- 11.44 %false
- 22.02 %false
- 31.04 %false
- 42.25 %true
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Answer : 4. "2.25 %"
Explanation :
Answer: D) 2.25 % Explanation: SP of each car is Rs. 404415, he gains 15% on first car and losses 15% on second car. In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (15)(15)/100 % = 2.25%

