Quantitative Aptitude Practice Question and Answer
8Q: How many numbers up to 101 and 300 are divisible by 11 ? 2181 05b5cc6d3e4d2b4197774e51d
5b5cc6d3e4d2b4197774e51d- 118true
- 220false
- 319false
- 417false
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Answer : 1. "18"
Explanation :
Answer: A) 18 Explanation: (300 – 101)/11 = 199/11 = 18 1/1118 Numbers.
Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 2181 05b5cc764e4d2b4197774fd80
5b5cc764e4d2b4197774fd80- 1100 mtsfalse
- 296 mtsfalse
- 398 mtstrue
- 4120 mtsfalse
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Answer : 3. "98 mts"
Explanation :
Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.
Q: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year ? 2179 05b5cc6e1e4d2b4197774ebf7
5b5cc6e1e4d2b4197774ebf7- 1Rs. 1100false
- 2Rs. 1200true
- 3Rs. 1000false
- 4Rs. 1840false
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Answer : 2. "Rs. 1200"
Explanation :
Answer: B) Rs. 1200 Explanation: P --- 10 ----- 600 P --- 5 ----- 300 3P --- 5 ----- 900 __________ 1200
Q: Salaries of Karthik, Arun and Akhil were in the ratio 4 : 5 : 6 respectively. If their salaries were increased by 50 per cent, 60 per cent and 50 per cent respectively, what will be the new ratio of the salaries of Akhil, Arun and Karthik ? 2175 05b5cc761e4d2b4197774fd2a
5b5cc761e4d2b4197774fd2a- 16 : 8 : 9false
- 28 : 6 : 9false
- 39 : 8 : 6true
- 46 : 5 : 4false
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Answer : 3. "9 : 8 : 6"
Explanation :
Answer: C) 9 : 8 : 6 Explanation: Given the salaries are in the ratio of 4 : 5 : 6 Now the salaries are increased by 50%, 60% and 50% respectively The New ratio of salaries will be 4 x (150/100) : 5 x (160/100) : 6 x (150/100) = 6 : 8 : 9 The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6
Q: The sides of a right-angled triangle are 12 cm, 16 cm, 20 cm respectively. A new right angle Δ is made by joining the midpoints of all the sides. This process continues for infinite then calculate the sum of the areas of all the triangles so made. 2175 05b5cc6b7e4d2b4197774d62e
5b5cc6b7e4d2b4197774d62e- 1312 sq.cmfalse
- 2128 sq.cmtrue
- 3412 sq.cmfalse
- 4246 sq.cmfalse
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Answer : 2. "128 sq.cm"
Explanation :
Answer: B) 128 sq.cm Explanation: Area = = 96 Sum of Area =
Q: 5/9 of the part of the population in a village are females. If 30 % of the females are married. The percentage of unmarried males in the total males is ? 2174 05b5cc72ce4d2b4197774f7a1
5b5cc72ce4d2b4197774f7a1- 162.5 %true
- 2125 %false
- 384.32 %false
- 446.87 %false
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Answer : 1. "62.5 %"
Explanation :
Answer: A) 62.5 % Explanation: Let total population = p number of females = 5p/9number of males =(p-5p/9) = 4p/9married females = 30% of 5p/9 = 30x5p/100x9 = p/6married males = p/6unmarried males =(4p/9-p/6) = 5p/18Percentage of unmarried males in the total males = {(5p/18)/4p/9}x100 = (5p/18)x(9/4p) = 125/2 % = 62.5%
Q: Sandeep got Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Saketh earned at the end of one year. If Sandeep invested Rs. 20000 for 6 months, whereas Saketh invested his amount for the whole year, the amount invested by Saketh? 2174 05b5cc6a6e4d2b4197774cdd9
5b5cc6a6e4d2b4197774cdd9- 1Rs. 5000true
- 2Rs. 6200false
- 3Rs. 8100false
- 4R. 7600false
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Answer : 1. "Rs. 5000"
Explanation :
Answer: A) Rs. 5000 Explanation: Let the amount invested by saketh = RS. p Now, that of sandeep = 20,000 x 6 saketh = 12 x p Ratio of their earnings = 120000 : 12p = 6000 : (9000 - 6000) => 12000012p = 60003000 => p= Rs. 5000 Hence, the amount investe by saketh = Rs. p = Rs. 5000.
Q: A man can row upstream at 16 km/hr and downstream at 24 km/hr. Find the speed of the current. 2173 05b5cc6bde4d2b4197774d942
5b5cc6bde4d2b4197774d942- 14 kmphtrue
- 26 kmphfalse
- 35 kmphfalse
- 43 kmphfalse
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Answer : 1. "4 kmph"
Explanation :
Answer: A) 4 kmph Explanation: Speed of the current = 24-16/2 = 8/2 = 4 km/hr.