Quantitative Aptitude Practice Question and Answer
8Q: Twelve percent of Kalyan's monthly salary is equal to the sixteen per cent of Nandu's monthly salary. Sarnesh's monthly salary is half that of Nandu's monthly salary. If sarnesh's annual salary is Rs. 1.08 lacs, What is Kalyan's monthly salary ? 2093 05b5cc72ce4d2b4197774f746
5b5cc72ce4d2b4197774f746- 115,000false
- 236,000false
- 324,000true
- 412,500false
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Answer : 3. "24,000"
Explanation :
Answer: C) 24,000 Explanation: Let K = Kalyan's monthly salaryN = Nandu's monthly salaryS = Sarnesh's monthly salary.Then from given data, 12% of K = 16% of NS = N/2 => N = 2SK = 16/12 x N = 16/12 x 2S= 16/6 x 1.08/12 = 16/6 x 0.09 = 0.24 lacs = 24,000
Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 2090 05b5cc764e4d2b4197774fd80
5b5cc764e4d2b4197774fd80- 1100 mtsfalse
- 296 mtsfalse
- 398 mtstrue
- 4120 mtsfalse
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Answer : 3. "98 mts"
Explanation :
Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.
Q: The Simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs.1875. What would be the simple interest accrued on an amount of Rs. 6875 at the same rate and Same period? 2090 05b5cc7c7e4d2b41977750d78
5b5cc7c7e4d2b41977750d78- 1Rs. 4,556.5false
- 2Rs. 5,025.25false
- 3Rs.5,245.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: It takes one minute to fill 2/7 th of a vessel. What is the time taken in minutes to fill the whole of the vessel ? 2089 05b5cc6d8e4d2b4197774e7fd
5b5cc6d8e4d2b4197774e7fd- 11/7 minfalse
- 27/2 mintrue
- 35/7 minfalse
- 47/5 minfalse
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Answer : 2. "7/2 min"
Explanation :
Answer: B) 7/2 min Explanation: Time taken to fill 2/7 = 1Then to fill full 1 = ?? = 1/(2/7) = 7/2 minutes.
Q: How many numbers up to 101 and 300 are divisible by 11 ? 2088 05b5cc6d3e4d2b4197774e51d
5b5cc6d3e4d2b4197774e51d- 118true
- 220false
- 319false
- 417false
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Answer : 1. "18"
Explanation :
Answer: A) 18 Explanation: (300 – 101)/11 = 199/11 = 18 1/1118 Numbers.
Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 2085 05b5cc73ae4d2b4197774f902
5b5cc73ae4d2b4197774f902- 114.69 cmfalse
- 229.39 cmtrue
- 318.65 cmfalse
- 422.21 cmfalse
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Answer : 2. "29.39 cm"
Explanation :
Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms. As speed is same, area of cross sections should be same. Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12 i.e πR2 = 6πR12 Here R = R and R1 = 12/2 = 6 ⇒R2 = 6×6×6 R = 14.696 => D = X = 14.696 * 2 = 29.3938 cm.
Q: The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is ? 2085 05b5cc6e2e4d2b4197774ec3e
5b5cc6e2e4d2b4197774ec3e- 12(6!)false
- 26! x 7false
- 36! x ⁷P₆true
- 4Nonefalse
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Answer : 3. "6! x ⁷P₆"
Explanation :
Answer: C) 6! x ⁷P₆ Explanation: We can initially arrange the six boys in 6! ways.Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways. Hence required number of ways = 6! x ⁷P₆
Q: P, Q, and R can do a job in 12 days together. If their efficiency of working be in the ratio 3 : 8 : 5, Find in what time Q can complete the same work alone? 2084 05b5cc698e4d2b4197774c61d
5b5cc698e4d2b4197774c61d- 136 daystrue
- 230 daysfalse
- 324 daysfalse
- 422 daysfalse
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Answer : 1. "36 days"
Explanation :
Answer: A) 36 days Explanation: Given the ratio of efficiencies of P, Q & R are 3 : 8 : 5 Let the efficiencies of P, Q & R be 3x, 8x and 5x respectively They can do work for 12 days. => Total work = 12 x 16x = 192x Now, the required time taken by Q to complete the job alone = 162x8x = 24 days.