Aptitude Question with Solved Answers for Competitive Exam

3 weeks ago 677 Views
NEW aptitude question with solved answers

If bank, ssc, upsc, railway and other competitive exams students face difficulties in solving Aptitude questions related paper. So in this blog, here are the important aptitude question with solved answers, so that you can solve aptitude section and its difficulty level. 

These aptitude questions with solutions are given here will be useful for exam preparations. You should try to solve fist your self and improve your mental ability with the help of these questions.

Important Solved Aptitude Questions with Answers:


1. 106 × 106 – 94 × 94 =?

Solution

106 × 106 – 94 × 94

=(106)2 – (94)2 = (106 + 94) (106 – 94) [(a+b)2+(a-b)2=2(a2+b2)]

= (200 × 12) = 2400

Q.2. H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 × 35 × 52 × 72. The third number is 

3240 = 2­3×34×5; 3600 = 24×32×52; H.C.F = 36 = 22×32.

Since H.C.F is the product of lowest powers of common factors, so the third number must have (22×32) as its factor.

Since L.C.M. is the product of highest powers of common prime factors. So the third number must have 35 and 72 as its factors. 

⸫ Third number = 22×35×72.

Q.3. Evaluate:

(1) 35 ÷ .07  

(2) 2.5 ÷ 0.0005  

(3) 136.09 ÷ 43.9

Solution :

(1) 35/.07 = 35*100 / .07*100 = 3500/7 = 500.

(2) 2.5/ 0.0005 = 2.5*10000 / 0.0005*10000 = 25000/5 = 5000.

(3) 136.09/43.9 = 136.09*10/43.9*10 = 1360.9/439 = 3.1.

Q.4. Simplify : b-[b-(a+b)-{b-(b-a-b)}+2a].

Given expression = b-[b-(a+b)-{b-(b-a+b)}+2a]

                                = b-[b-a-b-{b-2b+a}+2a]

                                 = b-[-a-{b-2b+a+2a}]

                                  = b-[-a-{-b+3a}]

                                  = b-[-a+b-3a]

                                = b-[-4a+b]= b+4a-b=4a.

Q.5. Simplify : 

$$\sqrt { [(12.1)^2-(8.1)^2]÷[(0.25)^2+(0.25)(19.95)]} \  $$

  $$ =\sqrt {{(12.1+8.1)(12.1-8.1)\over(0.25)(0.25+19.95)} } \  $$

  $$ =\sqrt { {20.2*4\over0.25*20.2}} \ $$

  $$=\sqrt {{4\over0.25} } \ $$

  $$ =\sqrt {400\over25} \ $$

   $$ =\sqrt {16} \ $$

  $$=4$$

Q.6. Of the tree number, second is twice the first and is also thrice the third. If the average of the three numbers is 44, find the largest number.

Solution :

Let the third number be x. Then, second number = 3x. First number = 3x/2

⸫ x+3x+ 3x/2 = (44*3) or 11x/2 = 44*3 or x = 24.

So, largest number = 2nd number = 3x = 72.

Q.7. The sum of a rational number and its reciprocal is 13/6. Find the number.

Solution

Let the number be x.

Then x+ 1/x  = 13/6 ↔ x2+1/x = 13/6 ↔ 6x2-13x+6=0

↔ 6x2-9x-4x+6=0 ↔ (3x-2)(2x-3)=0

↔ x = 2/3 or x = 3/2.

Hence, the required number is 2/3 or 3/2

If you want to ask anything regarding aptitude questions with solutions, you can ask me in the comment section without any hesitation. Visit on the next page for more practice with solutions.

Showing page 1 of 4

    Choose from these tabs.

    You may also like

      Report Error : Aptitude Question with Solved Answers for Competitive Exam

    Please Enter Message
    Error Reported Successfully